1031. Hello World for U (20)
Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, “helloworld” can be printed as:
h d
e l
l r
lowo
| That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters, then left to right along the bottom line with n2 characters, and finally bottom-up along the vertical line with n3 characters. And more, we would like U to be as squared as possible – that is, it must be satisfied that n1 = n3 = max { k | k <= n2 for all 3 <= n2 <= N } with n1 + n2 + n3 - 2 = N. |
Input Specification:
Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.
Output Specification:
For each test case, print the input string in the shape of U as specified in the description.
Sample Input:
helloworld!
Sample Output:
h !
e d
l l
lowor
代码如下：
#include<iostream>
#include<string>
using namespace std;
int main(){
string s;
cin>>s;
int n=s.size()+2;
int n2;
if(s.size()<5){
return 0;
}
if(n%3!=0){
n2=n;
while(n2%3!=0){
--n2;
}
int index=0;
for(int i=0,j=s.size()-1;i<n2/3-1;++i,--j){
cout<<s[i];
for(int q=1;q<=n-(n2/3)*2-2;++q){
cout<<" ";
}
cout<<s[j]<<endl;
++index;
}
int flag=s.size()-(index)*2;
while(flag) {
cout<<s[index++];
--flag;
}
}else{
for(int i=0,j=s.size()-1;i<n/3-1;++i,--j){
cout<<s[i];
for(int q=1;q<=(n/3-2);++q){
cout<<" ";
}
cout<<s[j]<<endl;
}
for(int i=n/3-1;i<=(n/3-1)*2;++i){
cout<<s[i];
}
}
return 0;
}
