1065. A+B and C (64bit) (20)

​ 时间限制

​ 100 ms

​ 内存限制

​ 65536 kB

​ 代码长度限制

​ 16000 B

​ 判题程序

​ Standard

​ 作者

​ HOU, Qiming

Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line “Case #X: true” if A+B>C, or “Case #X: false” otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

原文地址

代码如下

#include<iostream>
using namespace std;
int main(){

	int n;
	scanf("%d",&n);
	for(int i=1;i<=n;++i){
		long long a,b,c,sum=0;
		scanf("%lld%lld%lld",&a,&b,&c);
		sum=a+b;
		if(a>0&&b>0&&sum<=0){
			printf("Case #%d: true\n",i);
		}else if(a<0&&b<0&&sum>=0){
			printf("Case #%d: false\n",i);
		}else if(sum>c){
			printf("Case #%d: true\n",i);
		}else{
			printf("Case #%d: false\n",i);
		}
	}
	
	
	
	return 0;
}